In this problem we will pre calculate all the factorial values upto 20(because the constraint). Then greedily we will just check can we take the value of factorial of any number.
#include<bits/stdc++.h>
#define ll long long
#define pb push_back
#define mp make_pair
#define f0(n) for(int i=0;i<n;i++)
#define ms(x) memset(x,0,sizeof(x))
#define ins insert
#define IOS ios::sync_with_stdio(false);
using namespace std;
int main()
{
IOS
int t;
cin>>t;
ll fact[21];
fact[0] = 1;
for(int i=1;i<=20;i++)
{
fact[i] = fact[i-1]*i;
//cout << fact[i] << endl;
}
for(int tc=1;tc<=t;tc++)
{
ll n;
cin>>n;
vector<int>vec;
for(int i=20;i>=0;i--)
{
if(fact[i]<=n)
{
n-=fact[i];
vec.pb(i);
}
if(n==0) break;
}
sort(vec.begin(),vec.end());
cout << "Case "<< tc << ": ";
if(n!=0) {cout <<"impossible\n";continue;}
for(int i=0;i<vec.size();i++)
{
if(i>0 && i<vec.size())
cout << "+";
cout << vec[i] << "!";
}
cout << endl;
}
return 0;
}
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