In this problem we will pre calculate all the factorial values upto 20(because the constraint). Then greedily we will just check can we take the value of factorial of any number. 
#include<bits/stdc++.h>
#define ll long long
#define pb push_back
#define mp make_pair
#define f0(n) for(int i=0;i<n;i++)
#define ms(x) memset(x,0,sizeof(x))
#define ins insert
#define IOS ios::sync_with_stdio(false);
using namespace std;
int main()
{
    IOS
    int t;
    cin>>t;
    ll fact[21];
    fact[0] = 1;
    for(int i=1;i<=20;i++)
    {
        fact[i] = fact[i-1]*i;
        //cout << fact[i] << endl;
    }
    for(int tc=1;tc<=t;tc++)
    {
        ll n;
        cin>>n;
        vector<int>vec;
        for(int i=20;i>=0;i--)
        {
            if(fact[i]<=n)
            {
                n-=fact[i];
                vec.pb(i);
            }
            if(n==0) break;
        }
        sort(vec.begin(),vec.end());
        cout << "Case "<< tc << ": ";
        if(n!=0) {cout <<"impossible\n";continue;}
        for(int i=0;i<vec.size();i++)
        {
            if(i>0 && i<vec.size())
                cout << "+";
            cout << vec[i] << "!";
        }
        cout << endl;
    }
    return 0;
}
 
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